A lamp is rated 240 V, 60 W. Determine the resistance of the lamp when lit?

  • A 120\(\Omega\)
  • B 240\(\Omega\)
  • C 540\(\Omega\)
  • D 960\(\Omega\)
waec 2022physics

The correct answer is D. 960\(\Omega\)

P = 60w, V = 240v, R = ?

P = \(\frac{V^2}{R}\)

: 60 = \(\frac{240^2}{R}\)

→ R * 60 = 57,600

R = \(\frac{57,600}{60}\)

R = 960\(\Omega\)

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