A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound is 180, Find the molecular formula [H = 1, C = 12, O = 16)

  • A CH2O
  • B C3H6O3
  • C C6H12O6
  • D C6H12O3
jamb 2015chemistry

The correct answer is C. C6H12O6

C = 40%, 40/12 = 3.33

H = 6.7%, 6.7/1 = 6.7

O = 53.3%, 53.3/16 = 3.33

C = 3.33/3.33 = 1

H = 6.7/3.33 = 2

O = 3.33/3.33 = 1

(CH2O)n = 180

(12 + 2 + 16)n = 180

30n = 180

n = 6

= C6H12O6

Previous question Next question