In the electrolysis of CuSo4(g) using platinum electrode the reaction at the anode is

  • A 4H+ 4e - 2H2
  • B 4OH= 4e- + 2H2O + O2
  • C 2OH - 2e- = 2OH
  • D 2OH- + 2OH = 2H2O + O2
jamb 2015chemistry

The correct answer is B. 4OH= 4e- + 2H2O + O2

40H − 4e → 2H2O + O2is the reaction of sun at the anode in the electrolysis of CuSO4 (g) using platinum particles. Option A,C,D are not formed as a result of the equation

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