The number of atoms of chlorine present in 5.85g of NaCl is [Avogaro's Number = 6.02 x 1023]

  • A 6.02 x 1022
  • B 5.85 x 1023
  • C 6.02 x 1023
  • D 5.85 x 1024
jamb 1986chemistry

The correct answer is A. 6.02 x 1022

The number of atoms of chloride present in 5.85g of NaCl is 5.85 x 6.0 x 1023

= 6.02 x 1022

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