Copper sulphate solution is electolysed using platinum electrodes A. current of 0.193 amperes is passed for 2hrs. How many grams of copper are deposited? (cu = 63.5, F = 96500 coulombs)
The correct answer is A. 0.457g
Time = 2hrs 120mm = 120 x 60secs
current = 0.193amps
Quantity of electricity = 120 x 0.193
= 60 x 23.16
96,500 deposits 63.5 gms of Cu
60 x 23.2 will deposit \(\frac{63.5 \times 60 \times 23.2}{96500}\)
= 0.457
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