A sample of orange juice is found to have a PH of 3.80. What is the concentration of the hydroxide ion in the juice?

  • A 1.6 \(\times\) 10-4
  • B 6.3 \(\times\) 10-11
  • C 6.3 \(\times\) 10-4
  • D 1.6 \(\times\) 10-11
jamb 2017chemistry

The correct answer is B. 6.3 \(\times\) 10-11

PH = - Log[ H+ ]

PH + POH =14

POH = 14 - 3.8

POH = 10.2

POH = - Log[ OH- ]

10.2 = - Log[ OH- ]

10-10.2 = [ OH- ]

[ OH- ] = 6.3 x 10-11

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