An oxide XO2 has a vapour density of 32. What is the atomic mass of X?
The correct answer is B. 32
Molecular mass = vapour density X2
Mm of XO2 = x + 16(2) = x + 32
vapour density = 32
â´ x + 32 = 32 Ã 2
x + 32 = 64
x = 64 - 32
x = 32
â´ the relative molecular mass of X is 32
Relative molecular mass = vapour density à 2
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