0.07g of a hydride of carbon occupies 56.0cm3 at S.T.P. when vaporized and contains 14.29% by mass of hydrocarbon is(C = 12, H = 1)

  • A CH4
  • B C2H2
  • C C2H4
  • D C2H6
  • E C3H8
jamb 1982chemistry

The correct answer is C. C2H4

% of H2 = 14.29

% of C = 85.71

Divided by At wts

For H = (14.29)/(1) = 14.29

For C = (85.71)/(12) = 7.14

Dividing by smallest number we have the following:

For H (14.29)/(7.14) = 2

For C = (7.14)/(7.14) = 1

Emperical formula of the comp = CH2

wt of hydride taht will occupy 22400 cm is 22400 x 0.7

56 = 28 = mole wt of hydride

X(CH2) = 28

X(12 + 2) = 28 i.e 14x = 28x = 2

The formula of hydrocarbon is therefore C2H4

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