The oxidation state of Cr in K\(_2\)Cr\(_2\)O\(_7\) is?

  • A +7
  • B +6
  • C +5
  • D 4
jamb 2009chemistry

The correct answer is B. +6

Potassium dichromate, K\(_2\)Cr\(_2\)O\(_7\) 

→ [1 * 2] + [Cr * 2] + [-2 * 7] = 0

→ 2 + 2Cr - 14 = 0

→ 2Cr = 12

→Cr = \(\frac{12}{2}\) → 6

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