0.1 faraday of electricity deposited 2.95 g of nickel during electrolysis of an aqueous solution. Calculate the number of moles of nickel that will be deposited by 0.4 faraday? (Ni = 58.7)

0.1 faraday of electricity deposited 2.95 g of nickel during electrolysis of an aqueous solution.

Calculate the number of moles of nickel that will be deposited by 0.4 faraday?

(Ni = 58.7)

The correct answer is A. 0.20

0.1F â 2.95 g Ni = 0.4F â 11.8 g Ni

No of moles = (11.8)/(58.2) = 0.20 moles