2SO2(g) + O2(g) ↔ 2SO3(g). In the chemical reaction above, the substance that will increase the rate of production of sulphur (VI) oxide is

2SO_2(g) + O_2(g) ↔ 2SO_3(g). In the chemical reaction above, the substance that will increase the rate of production of sulphur (VI) oxide is

A manganese (IV) oxide
B finely divided iron
C vanadium (V) oxide
D nickel

jamb 1999 chemistry

The correct answer is C. vanadium (V) oxide

No explanation given

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