When a current I was passed through an electrolyte solution for 40 minutes, a mass X g of a univalent metal was deposited at the cathode. What mass of the metal will be deposited when a current 2I is passed through the solution for 10 minutes?

  • A X/4 g
  • B X/2 g
  • C 2X g
  • D 4X g

The correct answer is B. X/2 g

From M = zit

Where M = to the mass of the metal liberated

z = Is the electrochemical equivalent

∴ X g = 1 * 1 * 40 * 60

X g = 2400 I

Let Y represent the new mass

Y = 1*2I * 10 * 60

Y = 1200 I

Y/(X g) = 1200 I/2400 I

Y = X/2 g

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