RS(aq) + HF(aq) → RF(s) + HS(aq) ΔH = -65.7 kj mol(-1). From the equation above, it can be deduced that

RS_(aq) + HF_(aq) → RF_(s) + HS_(aq)

ΔH = -65.7 kj mol^(-1).

From the equation above, it can be deduced that

A the heat content of the reactants is lower than that of the products
B the heat content of the reactants is higher than that of the products
C the reaction is slow
D a large amount of heat is absorbed

jamb 1999 chemistry

The correct answer is B. the heat content of the reactants is higher than that of the products

No explanation given

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