<table border=\"2\"><tr><td></td><td>J</td><td>F</td><td>M</td><td>A</td><td>M</td><td>J</td><td>J</td><td>A</td><td>S</td><td>O</td><td>N</td><td>D</td></tr><tr><td>T<sup>o</sup>C</td><td>-11</td><td>-9</td><td>4</td><td>3</td><td>12</td><td>17</td><td>19</td><td>17</td><td>11</td><td>4</td><td>-2</td><td>-8</td></tr><tr><td>P(mm)</td><td>28</td><td>23</td><td>30</td><td>38</td><td>48</td><td>51</td><td>71</td><td>74</td><td>56</td><td>36</td><td>41</td><td>41</td></tr></table>T = Temperature P = precipitationThe annual temperature range at the station is

The answer is C. 30<sup>o</sup>C.

JFMAMJJASONDToC-11-94312171917114-2-8P(mm)282330384851717456364141 T = Temperature P = precipitation The annual temperature range at the station is

T = Temperature P = precipitation The annual temperature range at the station is

The correct answer is C. 30^oC

No explanation given