If a \(\ast\) b = + \(\sqrt{ab}\), evaluate 2 \(\ast\)(12 \(\ast\) 27)

  • A 12
  • B 9
  • C 6
  • D 2
jamb 1995mathematics

The correct answer is C. 6

Given the operation \(\ast\) defined as \(a \ast b = + \sqrt{ab}\), let's evaluate \(2 \ast (12 \ast 27)\):

1. \(12 \ast 27 = + \sqrt{12 \cdot 27} = + \sqrt{324} = + 18\)
2. \(2 \ast (12 \ast 27) = 2 \ast 18 = + \sqrt{2 \cdot 18} = + \sqrt{36} = + 6\)

So, the result of \(2 \ast (12 \ast 27)\) is + 6.

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