\(\begin{array}{c|c} x & 1 & 2 & 3 & 4 & 5 \\ \hline f & y + 2 & y - 2 & 2y - 3 & y + 4 & 3y - 4\end{array}\)

This table shows the frequency distribution of a data if the mean is \(\frac{43}{14}\) find y

  • A 1
  • B 2
  • C 3
  • D 4
jamb 1994mathematics

The correct answer is B. 2

Mean = \(\frac{\sum fx}{\sum f}\)

\(\therefore \frac{28y - 13}{8y - 2} = \frac{43}{14}\)

\(\implies 14(28y - 13) = 43(8y - 2)\)

\(392y - 182 = 344y - 86\)

\(392y - 344y = -86 + 182 \implies 48y = 96\)

\(y = 2\)

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