Score (x) | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
---|---|---|---|---|---|---|---|
Freq (f) | 5 | 7 | 3 | 7 | 11 | 6 | 7 |
The correct answer is A. 3.26
The mean of the data can be calculated by summing the products of each score and its frequency, and then dividing by the total frequency. In MathJax, this can be written as follows:
\(\text{Mean} = \frac{\sum_{i=1}^{n} x_i f_i}{\sum_{i=1}^{n} f_i}\)
where `n` is the number of distinct scores, `xi` is the `i-th` score, and `fi` is the frequency of the `i-th` score.
Substituting the values from the table into this formula, we get:
\(\text{Mean} = \frac{(0)(5) + (1)(7) + (2)(3) + (3)(7) + (4)(11) + (5)(6) + (6)(7)}{5 + 7 + 3 + 7 + 11 + 6 + 7} = \frac{150}{46} \approx 3.26\)
So, the mean of the data is approximately 3.26
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