If U = (1, 2, 3, 6, 7, 8, 9, 10) is the universal set. E = (10, 4, 6, 8, 10) and F = {x: 1x\(^{2}\) = 2\(^{6}, x is odd}. Find (E ∩ F)', where ' means the complement of a set.

  • A (0)
  • B U
  • C (8)
  • D \(\phi\)
jamb 1992mathematics

The correct answer is D. \(\phi\)

U = (1, 2, 3, 6, 7, 8, 9, 10)

E = (10, 4, 6, 8, 10)

F = (x : x\(^2\) = 2\(^6\), x is odd)

∴ F = \(\phi\) Since x\(^2\) = 2\(^6\) = 64

x = \(\pm 8\) which is even

∴ E ∩ F = \(\phi\) Since there are no common elements

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