A group of market women sell at least one of yam, plantain, and maize. 12 of them sell maize, 10 sell yam, and 14 sell plantain. 5 sell plantain and maize, 4 sell yam and maize, 2 sell yam and plantain only while 3 sell all the three items. How many women are in the group?
The correct answer is C. 18
Let's represent the three items as M for maize, Y for yam, and P for plantain.
The number of women who sell only maize and yam is calculated by subtracting the number of women who sell all three items from the number of women who sell maize and yam, which gives us 4-3 = 1.
Similarly, the number of women who sell only maize and plantain is 5-3 = 2, and the number of women who sell only yam and plantain is given as 2.
To find the number of women who sell only one item, we subtract the number of women who sell that item along with at least one other item from the total number of women who sell that item. This gives us 6 women who sell only maize, 4 women who sell only yam, and 7 women who sell only plantain.
Finally, we add up all the numbers to find the total number of market women in the group: 6 + 4 + 7 + (1 + 2 + 2 + 3) = 25 market women.
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