Find the sum to infinity to the following series 3 + 2 + \(\frac{4}{3}\) + \(\frac{8}{9}\) + \(\frac{16}{17}\) + .....
The correct answer is D. 9
The given series is a geometric series where each term is obtained by multiplying the previous term by a common ratio.
The first term \(a\) is 3 and the common ratio \(r\) is \(\frac{2}{3}\).
The sum of an infinite geometric series is given by the formula: \[\text{Sum} = \frac{a}{1 - r}\]
Substitute the values \(a = 3\) and \(r = \frac{2}{3}\) into the formula:
\[\text{Sum} = \frac{3}{1 - \frac{2}{3}} = \frac{3}{\frac{1}{3}} = 3 \times 3 = 9\]
So, the sum of the given series to infinity is 9.
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