If x + \(\frac{1}{x}\) = 4, find \(x^2+ \frac{1}{x^2}\)

  • A 16
  • B 14
  • C 12
  • D 9
jamb 1990mathematics

The correct answer is B. 14

x + \(\frac{1}{x}\) = 4, find x 2x + \(\frac{1}{x}\) = 4, find x + \(\frac{1}{x^2}\) = (x + \(\frac{1}{x}\)) 2= (x + \(\frac{1}{x}\)) = x 2= x + \(\frac{1}{x^2}\) + 2 x 2x + \(\frac{1}{x^2}\) = ( x + \(\frac{1}{x^2}\)) 2+ \(\frac{1}{x^2}\) = ( x + \(\frac{1}{x^2}\)) - 2 = (4) 2= (4) - 2 = 16 - 2 = 14

Previous question Next question