If the surface area of a sphere increased by 44%, find the percentage increase in diameter
The correct answer is D. 20
The surface area of a sphere is given by the formula A = 4πr^2, where r is the radius of the sphere.
The diameter of the sphere is equal to 2r.
If the surface area of the sphere increased by 44%, then the new surface area is 1.44A.
Substituting the formula for the surface area into this expression, we get 1.44A = 1.44(4πr^2) = 4π(1.2r)^2.
This shows that the new radius of the sphere is 1.2r, which means that the radius increased by 20%.
Since the diameter is equal to 2r, it also increased by 20%.
Therefore, the percentage increase in diameter is 20%
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