if a = -3, b = 2, c = 4, evaluate \(\frac{a^3 - b^3 - c^{\frac{1}{2}}}{b - a - c}\)

  • A 37
  • B \(\frac{-37}{5}\)
  • C \(\frac{37}{5}\)
  • D -37
jamb 1988mathematics

The correct answer is D. -37

\(\frac{a^{3} - b^{3} - c^{\frac{1}{2}}}{b - a - c} = \frac{(-3)^{3} - (2)^{3} - 4^{\frac{1}{2}}}{2 - (-3) - 4}\)

= \(\frac{-37}{1} = -37\)

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