If (g(y)) = \(\frac{y - 3}{11}\) + \(\frac{11}{y^2 - 9}\). what is g(y + 3)?

  • A \(\frac{y}{11} + \frac{11}{y(y + 6)}\)
  • B \(\frac{y}{11} + \frac{11}{y(y + 3)}\)
  • C \(\frac{y + 30}{11} + \frac{11}{y(y + 3)}\)
  • D \(\frac{y + 3}{11} + \frac{11}{y(y - 6)}\)
jamb 1988mathematics

The correct answer is A. \(\frac{y}{11} + \frac{11}{y(y + 6)}\)

Given \(g(y) = \frac{y - 3}{11} + \frac{11}{y^2 - 9}\), to find \(g(y + 3)\), substitute \(y\) with \(y + 3\) in the expression:

\(g(y + 3) = \frac{y + 3 - 3}{11} + \frac{11}{(y + 3)^2 - 9}\).

Simplify:

\(g(y + 3) = \frac{y}{11} + \frac{11}{y^2 + 6y + 9 - 9}\).

\(g(y + 3) = \frac{y}{11} + \frac{11}{y(y + 6)}\).

Therefore, \(g(y + 3) = \frac{y}{11} + \frac{11}{y(y + 6)}\)

Previous question Next question