The solutions of \(x^2\) - 2x - 1 = 0 are the points of intersection of two graphs. if one of the graphs is y = 2 + x - x2, find the second graph

  • A y = 1 - x
  • B y = 1 + x
  • C y = x - 1
  • D y = 3x + 3
jamb 1988mathematics

The correct answer is A. y = 1 - x

The second graph is 

\((x^{2} - 2x - 1) + (2 + x - x^{2})\)

= \(1 - x\)

Previous question Next question