The curve \(y = x^2 - 6x + 5\) is a parabola that opens upwards, since the coefficient of \(x^2\) is positive. The minimum point of the parabola is at the vertex.

The x-coordinate of the vertex (h) can be found using the formula \(h = -\frac{b}{2a}\), where \(a\) and \(b\) are the coefficients of \(x^2\) and \(x\), respectively. In this case, \(a = 1\) and \(b = -6\), so \(h = -\frac{-6}{2 \times 1} = 3\).

Substituting \(x = 3\) into the equation gives the minimum value of y:

\(y = (3)^2 - 6(3) + 5 = 9 - 18 + 5 = -4\)

So, the minimum point on the curve is at (3, -4)