To convert a number from base two to base ten, we can use positional notation and sum up each digit multiplied by its place value.

In this case, we have:

\(101101 \text{ (base two)} = (1 \times (2^5)) + (0 \times (2^4)) + (1 \times (2^3)) + (1 \times (2^2)) + (0 \times (2^1)) + (1 \times (2^0))\)

\(= (1 \times 32) + (0 \times 16) + (1 \times 8) + (1 \times 4) + (0 \times 2) + (1 \times 1)\)

\(= 32 + 8 + 4 + 1\)

\(= 45.\)

Therefore, in base ten, this number equals 45, and the correct answer is C.