Given that \(p = 1 + \sqrt{2}\) and \(q = 1 - \sqrt{2}\), evaluate \(\frac{p^{2} - q^{2}}{2pq}\).
The correct answer is D. -2√2
Given that \(p = 1 + \sqrt{2}\) and \(q = 1 - \sqrt{2}\), we can evaluate the expression \(\frac{p^{2} - q^{2}}{2pq}\) as follows:
First, let's calculate the numerator
\(p^{2} - q^{2}\)
\(p^{2} - q^{2}= (1 + \sqrt{2})^2 - (1 - \sqrt{2})^2 \)
\( 1 + 2\sqrt{2} + 2 - (1 - 2\sqrt{2} + 2) \)
\(= 4\sqrt{2}\)
Now, let's calculate the denominator 2pq:
\(2pq= 2(1 + \sqrt{2})(1 - \sqrt{2}) \)
\(= 2(1 - (\sqrt{2})^2) = -2\)
Therefore, the value of the expression is:
\(\frac{p^{2} - q^{2}}{2pq} &= \frac{4\sqrt{2}}{-2} = -2\sqrt{2}
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