Find P, if \(451_6-P_7=305_6\)
The correct answer is B. \(116_7\)
1. \(451_{6} - P_{7} = 305_{6}\)
2. \(P_{7} = 451_{6} - 305_{6}\)
3. \(P_{7} = 142_{6}\)
4. Convert \(142_{6} = 1 \cdot 6^{2} + 4 \cdot 6^{1} + 2 \cdot 6^{0}\)
5. \(= 36 + 24 + 2\)
6. \(= 62\)
7. Convert \(62_{10}\) to base 7:
\(\frac{62}{7} = 8 \text{ R } 6\)
\(\frac{8}{7} = 1 \text{ R } 1\)
\(\frac{1}{7} = 0 \text{ R } 1\)
8. Therefore, \(P_{7} = 116_{7}\).
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