If \(321_4\) is divided by \(23_4\) and leaves a remainder r, what is the value of r?
The correct answer is C. 2
To solve this problem, we can first convert the numbers from base 4 to base 10. The number \(321_4\) in base 10 is equal to \(34^2 + 24^1 + 14^0 = 57\). The number \(23_4\) in base 10 is equal to \(24^1 + 34^0 = 11\). So, when 57 is divided by 11, the remainder is 2.
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