What is the mean of the data t, 2t-1, t-2, 2t -1, 4t and 2t+2?
The correct answer is D. 2t-1/3
To find the mean of the given data, you need to add up all the values and then divide by the number of values.
The data is: \(t, 2t-1, t-2, 2t - 1, 4t, 2t+2\)
Sum of the values = \(t + (2t-1) + (t-2) + (2t - 1) + 4t + (2t+2)\)
= \(12t - 2\)
Number of values = 6
Mean = Sum of values / Number of values
Mean = \(\frac{12t - 2}{6}\)
Mean = \(2t - \frac{1}{3}\)
So, the mean of the data is \(2t - \frac{1}{3}}\).
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