To find the equation of a line parallel to \(y = -4x + 2\) passing through the point (2, 3), we can use the fact that parallel lines have the same slope. The given line has a slope of -4.

The point-slope form of a linear equation is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line and \(m\) is the slope.

Plugging in the values \((x_1, y_1) = (2, 3)\) and \(m = -4\), we get:

\(y - 3 = -4(x - 2)\)

Simplifying:

\(y - 3 = -4x + 8\)

Adding 3 to both sides:

\(y = -4x + 11\)

So, the equation of the line parallel to \(y = -4x + 2\) passing through (2, 3) is \(y = -4x + 11\)