Make Q the subject of formula if p = \(\frac{M}{5}\)(X + Q) + 1

  • A \(\frac{5P - MX + 5}{M}\)
  • B \(\frac{5P - MX - 5}{M}\)
  • C \(\frac{5P + MX + 5}{M}\)
  • D \(\frac{5P + MX - 5}{M}\)
jamb 2010mathematics

The correct answer is B. \(\frac{5P - MX - 5}{M}\)

p = \(\frac{M}{5}\)(X + Q) + 1

P - 1 = \(\frac{M}{5}\)(X + Q)

\(\frac{5}{M}\)(p - 1) = X + Q

\(\frac{5}{M}\)(p - 1)- x = Q

Q = \(\frac{5(p -1) - Mx}{M}\)

= \(\frac{5p - 5 - Mx}{M}\)

= \(\frac{5p - Mx - 5}{M}\)

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