The expression \(27x^3 - 8y^3\) can be factored using the difference of cubes formula, which states that \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\). In this case, we have \(a = 3x\) and \(b = 2y\), so we get:

\(27x^3 - 8y^3 = (3x)^3 - (2y)^3 = (3x - 2y)((3x)^2 + (3x)(2y) + (2y)^2) = (3x - 2y)(9x^2 + 6xy + 4y^2)\)

So, the other factor is **3x - 2y**