Calculate \(3310_5 - 1442_5\)

  • A \(1313_5\)
  • B \(2131_5\)
  • C \(4302_5\)
  • D \(1103_5\)

The correct answer is A. \(1313_5\)

To calculate \(3310_5 - 1442_5\), we can first convert both numbers to base 10, perform the subtraction, and then convert the result back to base 5. The number \(3310_5\) can be converted to base 10 as follows: \(3 \times 5^3 + 3 \times 5^2 + 1 \times 5^1 + 0 \times 5^0 = 375 + 75 + 5 + 0 = 455\). The number \(1442_5\) can be converted to base 10 as follows: \(1 \times 5^3 + 4 \times 5^2 + 4 \times 5^1 + 2 \times 5^0 = 125 + 100 + 20 + 2 = 247\). Subtracting these two numbers in base 10, we get \(455 - 247 = 208\). Now, we can convert the result back to base 5. To do this, we can repeatedly divide the number by the base (5) and write down the remainders until the quotient is zero. The remainders, read in reverse order, give us the digits of the number in base 5. Dividing \(208\) by \(5\), we get a quotient of \(41\) and a remainder of \(3\). Dividing \(41\) by \(5\), we get a quotient of \(8\) and a remainder of \(1\). Dividing \(8\) by \(5\), we get a quotient of \(1\) and a remainder of \(3\). Finally, dividing \(1\) by \(5\), we get a quotient of \(0\) and a remainder of \(1\). Reading the remainders in reverse order, we get that the result of the subtraction is \(1313_5\).

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