A feasible cell was constructed by joining the two half cells below. Cu2+ (aq) + 2e- → Cu(s) Eo = - 0.76 V. What is the standard e.m.f. of the cell?

A feasible cell was constructed by joining the two half cells below. Cu2+ (aq) + 2e- → Cu(s) Eo = - 0.76 V. What is the standard e.m.f. of the cell?

A - 1.1V
B - 0.42V
C +0.42V
D +1.1V

waec 2001 chemistry

The correct answer is D. +1.1V

e.m.f. = + 0.34 -(-0.76) = 0.34 + 0.76 = +1.1V

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