What amount of electricity is required to deposit one mole of aluminium from a solution of AlCl3?

  • A One Faraday
  • B One ampere
  • C Three Faradays
  • D Three amperes

The correct answer is C. Three Faradays

AlCl3 → Al3+ + 3Cl-

At cathode:

Al3+ + 3e- → Al

3 mole of electrons corresponds 3 F charge

So, required charge =3 F

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