Find the equation of the line which passes through (-4, 3) and parallel to line y = 2x + 5.

  • A y = 2x + 11
  • B y = 3x + 11
  • C y = 3x - 5
  • D y = 2x - 11
waec 2016furthermathematics

The correct answer is A. y = 2x + 11

The gradient of the line y = 2x + 5 ;

\(\frac{\mathrm d y}{\mathrm d x} = 2\)

\(\frac{y - 3}{x - (-4)} = \frac{y-3}{x+4} = 2\)

\(y - 3 = 2(x + 4) \implies y = 2x + 11\)

Previous question Next question