Solve (\(\frac{1}{9}\))\(^{x + 2}\) = 243\(^{x - 2}\)

  • A \(\frac{7}{5}\)
  • B \(\frac{6}{7}\)
  • C \(\frac{-7}{6}\)
  • D \(\frac{-6}{7}\)
waec 2021furthermathematics

The correct answer is A. \(\frac{7}{5}\)

(\(\frac{1}{9}\))\(^{x + 2}\) = 243\(^{x - 2}\)

3\(^{-2(x + 2)}\) =  3\(^{5(x - 2)}\);

-2(x+2) = 5(x - 2)

-2x -4 = 5x - 10

-7x = -6

x =  \(\frac{6}{7}\)

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