If \(x^2+y^2+-2x-6y+5 =0\), evaluate dy/dx when x=3 and y=2.

  • A 2
  • B -2
  • C -4
  • D 4
waec 2022furthermathematics

The correct answer is A. 2

\(x^2+y^2+-2x-6y+5 =0\)

When differentiated:

\(x^2+y^2+-2x-6y+5 =0\) â†’ 2x + 2y - 2 - 6 = 0

where x=3 and y=2

2[3] + 2[2] - 8 = 0

6 + 4 - 8 = 2

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