IN the diagram, |LN| = 4cm, LNM = 90o and tan y = 2/3. What is the area of the ∆LMN?

  • A 24cm2
  • B 12cm2
  • C 10cm2
  • D 6cm2

The correct answer is B. 12cm2

\(tan \hspace{1mm}y = \frac{opp}{adj}=\frac{2}{3}\Rightarrow \frac{2}{3}=\frac{

LN}{MN}=\frac{4}{MN}\\

∴ MN = \frac{12}{2}=6\\

Area \hspace{1mm}of \hspace{1mm}\Delta LMN = \frac{1}{2}\times MN\times LN=\frac{1}{2}\times 6\times 4=12cm\)

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