A sector of a circle of radius 14cm containing an angle 60o is folded to form a cone. Calculate the radius of the base of the cone.

  • A \(5\frac{1}{2}cm\)
  • B \(4\frac{2}{3}cm\)
  • C \(3\frac{1}{2}cm\)
  • D \(2\frac{1}{3}cm\)
waec 2007mathematics

The correct answer is D. \(2\frac{1}{3}cm\)

\(r=\frac{\theta \times l}{360^{\circ }}\\

r=?, \theta =60^{\circ }\), l = radius of the orginal sector of a circle = 14cm

\(r=\frac{60\times 14}{360}=\frac{7}{3}=2\frac{1}{3}cm\)

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