What is the place value of 9 in the number 3.0492?

  • A \(\frac{9}{10000}\)
  • B \(\frac{9}{1000}\)
  • C \(\frac{9}{100}\)
  • D \(\frac{9}{10}\)
waec 2006mathematics

The correct answer is B. \(\frac{9}{1000}\)

The number 3.0492 has the digit 9 in the thousandth place.

Therefore, the place value of 9 in the number 3.0492 is \(\frac{9}{1000}\).

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