If loga270 - loga10 + loga \(\frac{1}{3}\) = 2, what is the value of a?

  • A 3
  • B 4
  • C 5
  • D 6
waec 2006mathematics

The correct answer is A. 3

loga270 - loga10 + loga\(\frac{1}{3}\) = 2

loga270 + loga\(\frac{1}{3}\) - loga10 = 2

loga(270\(\frac{\frac{1}{3}}{10}\)) = 2

loga9 = 2

aa = 9

a = \(\sqrt{9}\) = 3

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