If \(\log_{10}\)(6x - 4) - \(\log_{10}\)2 = 1, solve for x.

  • A 2
  • B 3
  • C 4
  • D 5
waec 2018mathematics

The correct answer is C. 4

\(\log_{10}\)(6x - 4) - \(\log_{10}\)2 = 1

\(\log_{10}\)(6x - 4) - \(\log_{10}\)2 = \(\log_{10}\)10

\(\log_{10}\)\(\frac{6x - 4}{2}\) - \(\log_{10}\)10

\(\frac{6x - 4}{2}\) = 10

6x - 4 = 2 x 10

= 20

6x = 20 + 4

6x = 20

x = \(\frac{24}{6}\)

x = 4

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