The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at randon scored either 4 or 7 goals.

  • A \(\frac{9}{25}\)
  • B \(\frac{1}{5}\)
  • C \(\frac{6}{25}\)
  • D \(\frac{2}{5}\)
waec 2018mathematics

The correct answer is A. \(\frac{9}{25}\)

Prob. (team scored 4 goals) = Prob. (team scored 7 goals) = \(\frac{3}{25}\)

Hence, probability that a team selected at random scored either 4 or 7 goals;

= \(\frac{6}{25} + \frac{3}{25}\)

= \(\frac{9}{25}\)

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