Solved the equation \(2x^2 - x - 6\) = 0

  • A x = \(\frac{-3}{2}\) or 2
  • B x = -2 or \(\frac{3}{2}\)
  • C x = -3 or 2
  • D x = 3 or -2
waec 2018mathematics

The correct answer is A. x = \(\frac{-3}{2}\) or 2

\(2x^2 - x - 6\) = 0

\(2x^2 - 4x + 3x - 6\) = 0

2x(x - 2) + 3(x - 2) = 0

(2x + 3) (x - 2) = 0

Either; 2x + 3 = 0 or x - 2 = 0

x = \(\frac{-3}{2}\) or x = 2

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