Simplify: \(\log_{10}\) 6 - 3 log\(_{10}\) 3 + \(\frac{2}{3} \log_{10} 27\)

  • A 3 \(\log_{10}^2\)
  • B \(\log_{10}^2\)
  • C \(\log_{10}^3\)
  • D 2 \(\log_{10}^3\)
waec 2019mathematics

The correct answer is B. \(\log_{10}^2\)

log\(_{10}\) 6 - log\(_{10}\)3\(^3\) + log\(_{10}\) (\(\sqrt[3]{27}\))\(^2\)

= log \(_{10}\) 6 - log \(_{10}\) 27 + log\(_{10}\) 9

= log\(_{10}\) \(\frac{6  \times 9}{27}\)

= log\(_{10}\)2

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