Find the quadratic equation whose roots are \(\frac{1}{2}\) and -\(\frac{1}{3}\)

  • A 3x\(^2\) + x + 1 = 0
  • B 6x\(^2\) + x - 1 = 0
  • C 3x\(^2\) + x - 1 = 0
  • D 6x\(^2\) - x - 1 = 0
waec 2020mathematics

The correct answer is D. 6x\(^2\) - x - 1 = 0

x = \(\frac{1}{2}\) and x = \(\frac{-1}{3}\) 

(2x - 1) = 0 and (3x + 1) = 0

(2x - 1) (3x + 1) = 0

6x\(^2\) - x - 1 = 0

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