In the diagram, XYZ is an equilateral triangle of side 6cm and Y is the midpoint of \(\overline{XY}\). Find tan (< XZT)

  • A \(\frac{1}{\sqrt{3}}\)
  • B \(\frac{\sqrt{3}}{2}\)
  • C \(\sqrt{3}\)
  • D \(\frac{1}{2}\)

The correct answer is A. \(\frac{1}{\sqrt{3}}\)

ZT = \(\sqrt{6^2 - 3^2}\)

ZT = \(\sqrt{27}\) = \(3\sqrt{3}\)

tan (< XZT) =  \(\frac{3}{3\sqrt{3}}\)

= - \(\frac{1}{\sqrt{3}}\)

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